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A person boarded an express train on 30th August 2015 at Ahmedabad for Trivandrum. The train departed from Ahmedabad at 13:30 hours and reached Trivandrum at 7:30 hours on 1st September 2015. If the distance between Ahmedabad and Trivandrum is 2268 km, the average speed of the train between the two stations was

A.
54 km / hr
B.
42 km / hr
C.
15 km / hr
D.
9 km / hr

Solution:

Concept: Speed = Distance/TimeAverage Speed = (Total distance covered / Total time taken)Given:Time is given in 24hrs format.Train departure time from Ahmedabad: 30th August, 13:30 hours.Arrival time of the train at Trivandrum: 1st September, 7:30 hours.The distance between Ahmedabad and Trivandrum is 2268 km.Explanation:Time is taken for the complete journey:From 30th August, 13:30 hours to 31st August, 13:30 hours = 24 hoursFrom 31st August, 13:30 hours to 1st September, 1:30 hours = 12 hoursFrom 1st September, 1:30 hours to 1st September, 7:30 hours = 6 hoursTotal time is taken = 42 hoursAverage Speed = (Total distance covered / Total time taken) = 2268 km/42 hrs = 54 km/hrThus, the average speed of the bus during the entire journey is 54 km/hr.

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