Question Bank - Mathematics

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Evaluate:- ?sin x sec2x dx

A.
sin x + c
B.
tan x + c
C.
cot x + c
D.
sec x + c

Solution:

Concept:Relation and formula used:sec x = \(\frac{1}{cos x}\)tan x = \(\frac{sinx}{cosx}\)?sec x tan x dx = sec xCalculation:Let, I = ?sec2x sin x dx ? I = \(\int sec x \frac{1}{cos x}sinx dx \)? I = \(\int sec x tan x dx\) ? I = sec x + c? The value of ?sec2x sin x dx = sec x + c

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