Question Bank - Mathematics

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Find the equation of a straight line passing through (3, 4) and having slope 3.

A.
3x - y - 5 = 0
B.
3 x - y + 9 = 0
C.
x - 3y - 9 = 0
D.
3x - y - 9 = 0

Solution:

Concept used:The general equation of a line is y = mx + c where m is the slope and c is any constantThe slope of parallel lines is equal.The slope of the perpendicular line have their product = “1 Equation of a line with slope m and passing through (x1, y1)(y “ y1) = m (x “ x1)Calculation:Given the line has the slope 3 and passes through (3, 4)? Equation of the line is(y “ y1) = m(x “ x1)? y “ 4 = 3 (x “ 3)? y “ 4 = 3x “ 9? y “ 3x + 5 = 0 or 3x - y - 5 = 0

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