Question Bank - Mathematics

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In how many ways can a team of 5 players be selected out of 9 players so as to exclude two particular players ?

A.
14
B.
21
C.
35
D.
42

Solution:

Given:5 members be selected out of 9 membersTwo particular members must always be excludedFormula used:nCr = n!/(n “ r)! r!Calculation:According to the question, Two members have always been excluded then actually we are choosing7 members and the number of members chosen in 5 ways7C5 = 7!/(7 “ 5)! 5!?(7 × 6 × 5!)/(5! × 2!)? (7 × 6)/2? 7 × 3? 21? The number of ways is 21.

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