Concept:Probability of occurrence of the event:P(E) = \(\frac{n(E)}{n(S)}\)Where,n(E) = Number of favorable outcomen(S) = Number of possible outcomeConditional probability:of two events is given by P(A|B) = \(\displaystyle \frac{n (A \cap B)}{n(B)}\)P(A|B) represents the probability of occurrence of A given B has occurred.Calculation:Let, G be the event that the first applicant interviewed is a graduate.T be the event that the first applicant interviewed has at least 3 years of experience.G? is the event that the first applicant interviewed is not a graduateT? is the event that the first applicant interviewed has less than three years of experienceNow, from the table we have,Number of applicants who are not graduates, \(n (\overline G )\) = 27 + 9 = 36Number of applicants who are not graduates and have less than three years of experience, \(n ( \overline T \cap \overline G )\) = 27Total number of applicants n(S) = 90So the required probability is given by,\(P(\overline T | \overline G)\) = \(\displaystyle \frac{P(\overline T \cap \overline G )}{P(\overline G)}\) = \(\displaystyle \frac{\frac{n ( \overline T \cap \overline G )}{n(S)}}{\frac{n (\overline G )}{n(S)}} \)\(\Rightarrow P(\overline T | \overline G)= \frac{n ( \overline T \cap \overline G )}{n (\overline G )} =\frac{27}{36}=\frac{3}{4}\)\(P (G \cap \overline T)\) equal to \(\displaystyle \frac{3}{4}\).